8=-16t^2+264

Solution for 8=-16t^2+264 equation:

8=-16t^2+264

We move all terms to the left:

8-(-16t^2+264)=0

We get rid of parentheses

16t^2-264+8=0

We add all the numbers together, and all the variables

16t^2-256=0

a = 16; b = 0; c = -256;
Δ = b2-4ac
Δ = 02-4·16·(-256)
Δ = 16384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16384}=128$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-128}{2*16}=\frac{-128}{32}
=-4
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+128}{2*16}=\frac{128}{32}
=4
$